Find the product. Simplify your answer. (3g + 2)(3g - 2) ______

Identify Special Case: Identify the special case that applies here. (3g + 2)(3g - 2) is in the form of (a + b)(a - b). Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (3g + 2)(3g - 2) with (a + b)(a - b). a = 3g b = 2Apply Difference of Squares: Apply the difference of squares to expand (3g + 2)(3g - 2). (a + b)(a - b) = a^2 - b^2 (3g + 2)(3g - 2) = (3g)^2 - 2^2Simplify Expression: Simplify (3g)^2 - 2^2. (3g)^2 - 2^2 = (3g * 3g) - (2 * 2) = 9g^2 - 4

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Find the product. Simplify your answer. $\newline$ $(3g + 2)(3g - 2)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3g + 2)(3g - 2)

Identify Special Case: Identify the special case that applies here. $\newline$ $(3g + 2)(3g - 2)$ is in the form of $(a + b)(a - b)$ . $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(3g + 2)(3g - 2)$ with $(a + b)(a - b)$ . $a = 3g$ $b = 2$
Apply Difference of Squares: Apply the difference of squares to expand $(3g + 2)(3g - 2)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(3g + 2)(3g - 2) = (3g)^2 - 2^2$
Simplify Expression: Simplify $(3g)^2 - 2^2.$ $(3g)^2 - 2^2 = (3g \times 3g) - (2 \times 2)$ $= 9g^2 - 4$