Find the product. Simplify your answer. (3d+4)(3d-4)

Identify Special Case: Identify the special case that applies to the given expression. The expression (3d+4)(3d-4) is in the form of (a+b)(a-b). Special case: (a+b)(a-b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (3d+4)(3d-4) with (a+b)(a-b). a = 3d b = 4Apply Formula: Apply the difference of squares formula to expand (3d+4)(3d-4). (a+b)(a-b) = a^2 - b^2 (3d+4)(3d-4) = (3d)^2 - (4)^2Simplify Expression: Simplify (3d)^2 - (4)^2. (3d)^2 - (4)^2 = (3d * 3d) - (4 * 4) = 9d^2 - 16

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Find the product. Simplify your answer.

(3d+4)(3d-4)

Find the product. Simplify your answer. $\newline$ $(3 d+4)(3 d-4)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3 d+4)(3 d-4)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(3d+4)(3d-4)$ is in the form of $(a+b)(a-b)$ . $\newline$ Special case: $(a+b)(a-b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(3d+4)(3d-4)$ with $(a+b)(a-b)$ . $a = 3d$ $b = 4$
Apply Formula: Apply the difference of squares formula to expand $(3d+4)(3d-4)$ . $\newline$ $(a+b)(a-b) = a^2 - b^2$ $\newline$ $(3d+4)(3d-4) = (3d)^2 - (4)^2$
Simplify Expression: Simplify $(3d)^2 - (4)^2.$ $(3d)^2 - (4)^2 = (3d \times 3d) - (4 \times 4)$ $= 9d^2 - 16$