Find the product. Simplify your answer. (3b - 3)(-4b^2 + 4b + 4) ______

Distribute terms in polynomials: We need to distribute each term in the first polynomial (3b - 3) to each term in the second polynomial (-4b^2 + 4b + 4). This is done by multiplying each term in the first polynomial by each term in the second polynomial.Multiply terms in first polynomial: First, multiply 3b by -4b^2 to get -12b^3.Combine like terms: Next, multiply 3b by 4b to get 12b^2.Simplify the expression: Then, multiply 3b by 4 to get 12b.Now, multiply -3 by -4b^2 to get 12b^2.Next, multiply -3 by 4b to get -12b.Finally, multiply -3 by 4 to get -12.Now, we combine like terms. The terms -12b^3 and 12b^2 from the first multiplication, 12b^2 and -12b from the second multiplication, and -12 from the third multiplication.Adding the like terms, we get -12b^3 + (12b^2 + 12b^2) + (12b - 12b) - 12.Simplify the expression to get -12b^3 + 24b^2 + 0b - 12.Since 0b is zero, it can be removed from the expression, leaving us with -12b^3 + 24b^2 - 12.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the product. Simplify your answer. $\newline$ $(3b - 3)(-4b^2 + 4b + 4)$

View step-by-step help

Full solution

Q. Find the product. Simplify your answer.

\newline

(3b - 3)(-4b^2 + 4b + 4)

Distribute terms in polynomials: We need to distribute each term in the first polynomial $3b - 3$ to each term in the second polynomial $-4b^2 + 4b + 4$ . This is done by multiplying each term in the first polynomial by each term in the second polynomial.
Multiply terms in first polynomial: First, multiply $3b$ by $-4b^2$ to get $-12b^3$ .
Combine like terms: Next, multiply $3b$ by $4b$ to get $12b^2$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .Now, multiply $-3$ by $-4b^2$ to get $12b^2$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .Now, multiply $-3$ by $-4b^2$ to get $12b^2$ .Next, multiply $-3$ by $4b$ to get $-12b$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ . Now, multiply $-3$ by $-4b^2$ to get $12b^2$ . Next, multiply $-3$ by $4b$ to get $-12b$ . Finally, multiply $-3$ by $4$ to get $4$ $1$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .Now, multiply $-3$ by $-4b^2$ to get $12b^2$ .Next, multiply $-3$ by $4b$ to get $-12b$ .Finally, multiply $-3$ by $4$ to get $4$ $1$ .Now, we combine like terms. The terms $4$ $2$ and $12b^2$ from the first multiplication, $12b^2$ and $-12b$ from the second multiplication, and $4$ $1$ from the third multiplication.
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ . Now, multiply $-3$ by $-4b^2$ to get $12b^2$ . Next, multiply $-3$ by $4b$ to get $-12b$ . Finally, multiply $-3$ by $4$ to get $4$ $1$ . Now, we combine like terms. The terms $4$ $2$ and $12b^2$ from the first multiplication, $12b^2$ and $-12b$ from the second multiplication, and $4$ $1$ from the third multiplication. Adding the like terms, we get $4$ $7$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .Now, multiply $-3$ by $-4b^2$ to get $12b^2$ .Next, multiply $-3$ by $4b$ to get $-12b$ .Finally, multiply $-3$ by $4$ to get $4$ $1$ .Now, we combine like terms. The terms $4$ $2$ and $12b^2$ from the first multiplication, $12b^2$ and $-12b$ from the second multiplication, and $4$ $1$ from the third multiplication.Adding the like terms, we get $4$ $7$ .Simplify the expression to get $4$ $8$ .
Simplify the expression: Then, multiply $3b$ by $4$ to get $12b$ .Now, multiply $-3$ by $-4b^2$ to get $12b^2$ .Next, multiply $-3$ by $4b$ to get $-12b$ .Finally, multiply $-3$ by $4$ to get $4$ $1$ .Now, we combine like terms. The terms $4$ $2$ and $12b^2$ from the first multiplication, $12b^2$ and $-12b$ from the second multiplication, and $4$ $1$ from the third multiplication.Adding the like terms, we get $4$ $7$ .Simplify the expression to get $4$ $8$ .Since $4$ $9$ is zero, it can be removed from the expression, leaving us with $12b$ $0$ .