Find the product. Simplify your answer. (2z + 2)(2z - 2) ______

Identify Form: Identify the form of the expression. The expression (2z + 2)(2z - 2) is in the form of (a + b)(a - b). Special case: (a + b)(a - b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (2z + 2)(2z - 2) with (a + b)(a - b). a = 2z b = 2Apply Formula: Apply the difference of squares formula to expand (2z + 2)(2z - 2). (a + b)(a - b) = a^2 - b^2 (2z + 2)(2z - 2) = (2z)^2 - (2)^2Simplify: Simplify (2z)^2 - (2)^2. (2z)^2 - (2)^2 = (2z * 2z) - (2 * 2) = 4z^2 - 4

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Find the product. Simplify your answer. $\newline$ $(2z + 2)(2z - 2)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2z + 2)(2z - 2)

Identify Form: Identify the form of the expression. $\newline$ The expression $(2z + 2)(2z - 2)$ is in the form of $(a + b)(a - b)$ . $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(2z + 2)(2z - 2)$ with $(a + b)(a - b)$ . $a = 2z$ $b = 2$
Apply Formula: Apply the difference of squares formula to expand $(2z + 2)(2z - 2)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(2z + 2)(2z - 2) = (2z)^2 - (2)^2$
Simplify: Simplify $(2z)^2 - (2)^2.$ $(2z)^2 - (2)^2 = (2z \cdot 2z) - (2 \cdot 2)$ $= 4z^2 - 4$