Find the product. Simplify your answer. (2w - 3)(2w + 3) ______

Recognize pattern: Recognize the pattern in the expression (2w - 3)(2w + 3). This is a difference of squares pattern, which can be written as (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify values: Identify the values of a and b. Compare (2w - 3)(2w + 3) with (a - b)(a + b). a = 2w b = 3Apply formula: Apply the difference of squares formula to expand (2w - 3)(2w + 3). (a - b)(a + b) = a^2 - b^2 (2w - 3)(2w + 3) = (2w)^2 - (3)^2Simplify: Simplify (2w)^2 - (3)^2. (2w)^2 - (3)^2 = (2w * 2w) - (3 * 3) = 4w^2 - 9

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Find the product. Simplify your answer. $\newline$ $(2w - 3)(2w + 3)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2w - 3)(2w + 3)

Recognize pattern: Recognize the pattern in the expression $(2w - 3)(2w + 3)$ . This is a difference of squares pattern, which can be written as $(a - b)(a + b)$ . Special case: $(a - b)(a + b) = a^2 - b^2$
Identify values: Identify the values of $a$ and $b$ . Compare $(2w - 3)(2w + 3)$ with $(a - b)(a + b)$ . $a = 2w$ $b = 3$
Apply formula: Apply the difference of squares formula to expand $(2w - 3)(2w + 3)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(2w - 3)(2w + 3) = (2w)^2 - (3)^2$
Simplify: Simplify $(2w)^2 - (3)^2.$ $(2w)^2 - (3)^2 = (2w \times 2w) - (3 \times 3)$ $= 4w^2 - 9$