Find the product. Simplify your answer. (2v - 3)(2v + 3) ______

Identify Special Case: Identify the special case for the given expression. The expression (2v - 3)(2v + 3) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (2v - 3)(2v + 3) with (a - b)(a + b). a = 2v b = 3Apply Difference of Squares Formula: Apply the difference of squares formula to expand (2v - 3)(2v + 3). (a - b)(a + b) = a^2 - b^2 (2v - 3)(2v + 3) = (2v)^2 - (3)^2Simplify Expression: Simplify (2v)^2 - (3)^2. (2v)^2 - (3)^2 = (2v * 2v) - (3 * 3) = 4v^2 - 9

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Find the product. Simplify your answer. $\newline$ $(2v - 3)(2v + 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2v - 3)(2v + 3)

Identify Special Case: Identify the special case for the given expression. $\newline$ The expression $(2v - 3)(2v + 3)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2v - 3)(2v + 3)$ with $(a - b)(a + b)$ . $a = 2v$ $b = 3$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(2v - 3)(2v + 3)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(2v - 3)(2v + 3) = (2v)^2 - (3)^2$
Simplify Expression: Simplify $(2v)^2 - (3)^2.$ $(2v)^2 - (3)^2 = (2v \times 2v) - (3 \times 3)$ $= 4v^2 - 9$