Find the product. Simplify your answer. (2u - 4)(2u + 4) ______

Identify form of expression: Identify the form of the expression. The expression (2u - 4)(2u + 4) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (2u - 4)(2u + 4) with (a - b)(a + b). a = 2u b = 4Apply difference of squares formula: Apply the difference of squares formula. Using the formula (a - b)(a + b) = a^2 - b^2, we get: (2u - 4)(2u + 4) = (2u)^2 - (4)^2Calculate squares of a and b: Calculate the squares of a and b. (2u)^2 = 4u^2 (4)^2 = 16Subtract squares of a and b: Subtract the square of b from the square of a. 4u^2 - 16

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Find the product. Simplify your answer. $\newline$ $(2u - 4)(2u + 4)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2u - 4)(2u + 4)

Identify form of expression: Identify the form of the expression. $\newline$ The expression $(2u - 4)(2u + 4)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2u - 4)(2u + 4)$ with $(a - b)(a + b)$ . $a = 2u$ $b = 4$
Apply difference of squares formula: Apply the difference of squares formula. $\newline$ Using the formula $(a - b)(a + b) = a^2 - b^2$ , we get: $\newline$ $(2u - 4)(2u + 4) = (2u)^2 - (4)^2$
Calculate squares of a and b: Calculate the squares of $a$ and $b$ . $(2u)^2 = 4u^2$ $(4)^2 = 16$
Subtract squares of $a$ and $b$ : Subtract the square of $b$ from the square of $a$ . $4u^2 - 16$