Find the product. Simplify your answer. (2t - 2)(2t + 2) ______

Identify Special Case: Identify the special case that applies here. The expression (2t - 2)(2t + 2) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (2t - 2)(2t + 2) with (a - b)(a + b). a = 2t b = 2Apply Difference of Squares Formula: Apply the difference of squares formula to expand (2t - 2)(2t + 2). (a - b)(a + b) = a^2 - b^2 (2t - 2)(2t + 2) = (2t)^2 - (2)^2Simplify Expression: Simplify (2t)^2 - (2)^2. (2t)^2 - (2)^2 = (2t * 2t) - (2 * 2) = 4t^2 - 4

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Find the product. Simplify your answer. $\newline$ $(2t - 2)(2t + 2)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2t - 2)(2t + 2)

Identify Special Case: Identify the special case that applies here. $\newline$ The expression $(2t - 2)(2t + 2)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2t - 2)(2t + 2)$ with $(a - b)(a + b)$ . $a = 2t$ $b = 2$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(2t - 2)(2t + 2)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(2t - 2)(2t + 2) = (2t)^2 - (2)^2$
Simplify Expression: Simplify ($2t)^ $2$ - ( $2$ )^ $2$ .(\newline$($2t)^ $2$ - ( $2$ )^ $2$ (\newline$= ( $2$ t \cdot $2$ t) - ( $2$ \cdot $2$ )(\newline\)= $4$ t^ $2$ - $4$