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Find the product. Simplify your answer.\newline(2r2)(2r+2)(2r - 2)(2r + 2)

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Q. Find the product. Simplify your answer.\newline(2r2)(2r+2)(2r - 2)(2r + 2)
  1. Identify values: Identify the values of aa and bb. Compare (2r2)(2r+2)(2r - 2)(2r + 2) with (ab)(a+b)(a - b)(a + b). a=2ra = 2r b=2b = 2
  2. Apply formula: Apply the difference of squares formula to expand (2r2)(2r+2)(2r - 2)(2r + 2).\newline(ab)(a+b)=a2b2(a - b)(a + b) = a^2 - b^2\newline(2r2)(2r+2)=(2r)2(2)2(2r - 2)(2r + 2) = (2r)^2 - (2)^2
  3. Simplify expression: Simplify (\(2r)^22 - (22)^22.(\newline\)(\(2r)^22 - (22)^22(\newline\)= (22r \cdot 22r) - (22 \cdot 22)(\newline\)= 44r^22 - 44

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