Find the product. Simplify your answer. (2j + 3)(2j - 3) ______

Identify Special Case: Identify the special case that applies to the given expression. The expression (2j + 3)(2j - 3) is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (2j + 3)(2j - 3) with (a + b)(a - b). a = 2j b = 3Apply Difference of Squares Formula: Apply the difference of squares formula to expand (2j + 3)(2j - 3). (a + b)(a - b) = a^2 - b^2 (2j + 3)(2j - 3) = (2j)^2 - (3)^2Simplify Expression: Simplify (2j)^2 - (3)^2. (2j)^2 - (3)^2 = (2j * 2j) - (3 * 3) = 4j^2 - 9

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Find the product. Simplify your answer. $\newline$ $(2j + 3)(2j - 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2j + 3)(2j - 3)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(2j + 3)(2j - 3)$ is in the form of $(a + b)(a - b)$ , which is a difference of squares. $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2j + 3)(2j - 3)$ with $(a + b)(a - b)$ . $a = 2j$ $b = 3$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(2j + 3)(2j - 3)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(2j + 3)(2j - 3) = (2j)^2 - (3)^2$
Simplify Expression: Simplify $(2j)^2 - (3)^2.$ $(2j)^2 - (3)^2 = (2j \cdot 2j) - (3 \cdot 3)$ $= 4j^2 - 9$