Find the product. Simplify your answer. (2h - 3)(2h + 3) ______

Identify Special Case: Identify the special case that applies to this problem. The expression (2h - 3)(2h + 3) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify a and b: Identify the values of a and b. Compare (2h - 3)(2h + 3) with (a - b)(a + b). a = 2h b = 3Apply Difference of Squares: Apply the difference of squares formula to expand (2h - 3)(2h + 3). (a - b)(a + b) = a^2 - b^2 (2h - 3)(2h + 3) = (2h)^2 - (3)^2Simplify Expression: Simplify (2h)^2 - (3)^2. (2h)^2 - (3)^2 = (2h * 2h) - (3 * 3) = 4h^2 - 9

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Find the product. Simplify your answer. $\newline$ $(2h - 3)(2h + 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2h - 3)(2h + 3)

Identify Special Case: Identify the special case that applies to this problem. $\newline$ The expression $(2h - 3)(2h + 3)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2h - 3)(2h + 3)$ with $(a - b)(a + b)$ . $a = 2h$ $b = 3$
Apply Difference of Squares: Apply the difference of squares formula to expand $(2h - 3)(2h + 3)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(2h - 3)(2h + 3) = (2h)^2 - (3)^2$
Simplify Expression: Simplify $(2h)^2 - (3)^2.$ $(2h)^2 - (3)^2 = (2h \times 2h) - (3 \times 3)$ $= 4h^2 - 9$