Find the product. Simplify your answer. (2g - 2)(2g + 2) ______

Identify Form: Identify the form of the expression. We have the expression (2g - 2)(2g + 2), which is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (2g - 2)(2g + 2) with (a - b)(a + b). a = 2g b = 2Apply Formula: Apply the difference of squares formula. Using the formula (a - b)(a + b) = a^2 - b^2, we get: (2g - 2)(2g + 2) = (2g)^2 - (2)^2Calculate Squares: Calculate the squares of a and b. (2g)^2 - (2)^2 = (2g * 2g) - (2 * 2) = 4g^2 - 4

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Find the product. Simplify your answer. $\newline$ $(2g - 2)(2g + 2)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2g - 2)(2g + 2)

Identify Form: Identify the form of the expression. $\newline$ We have the expression $(2g - 2)(2g + 2)$ , which is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(2g - 2)(2g + 2)$ with $(a - b)(a + b)$ . $a = 2g$ $b = 2$
Apply Formula: Apply the difference of squares formula. $\newline$ Using the formula $(a - b)(a + b) = a^2 - b^2$ , we get: $\newline$ $(2g - 2)(2g + 2) = (2g)^2 - (2)^2$
Calculate Squares: Calculate the squares of $a$ and $b$ . $(2g)^2 - (2)^2 = (2g \times 2g) - (2 \times 2) = 4g^2 - 4$