Find the product. Simplify your answer. (2f + 4)(2f - 4) ______

Identify Form: Identify the form of the expression. The expression (2f + 4)(2f - 4) is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (2f + 4)(2f - 4) with (a + b)(a - b). a = 2f b = 4Apply Formula: Apply the difference of squares formula to expand (2f + 4)(2f - 4). (a + b)(a - b) = a^2 - b^2 (2f + 4)(2f - 4) = (2f)^2 - (4)^2Simplify: Simplify (2f)^2 - (4)^2. (2f)^2 - (4)^2 = (2f * 2f) - (4 * 4) = 4f^2 - 16

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Find the product. Simplify your answer. $\newline$ $(2f + 4)(2f - 4)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2f + 4)(2f - 4)

Identify Form: Identify the form of the expression. $\newline$ The expression $(2f + 4)(2f - 4)$ is in the form of $(a + b)(a - b)$ , which is a difference of squares. $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(2f + 4)(2f - 4)$ with $(a + b)(a - b)$ . $a = 2f$ $b = 4$
Apply Formula: Apply the difference of squares formula to expand $(2f + 4)(2f - 4)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(2f + 4)(2f - 4) = (2f)^2 - (4)^2$
Simplify: Simplify $(2f)^2 - (4)^2.$ $(2f)^2 - (4)^2 = (2f \times 2f) - (4 \times 4)$ $= 4f^2 - 16$