Find the product. Simplify your answer. (2c + 4)(2c - 4) ______

Identify Special Case: Identify the special case that applies to the given expression. The expression (2c + 4)(2c - 4) is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (2c + 4)(2c - 4) with (a + b)(a - b). a = 2c b = 4Apply Difference of Squares Formula: Apply the difference of squares formula to expand (2c + 4)(2c - 4). (a + b)(a - b) = a^2 - b^2 (2c + 4)(2c - 4) = (2c)^2 - 4^2Simplify Expression: Simplify (2c)^2 - 4^2. (2c)^2 - 4^2 = (2c * 2c) - (4 * 4) = 4c^2 - 16

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Find the product. Simplify your answer. $\newline$ $(2c + 4)(2c - 4)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(2c + 4)(2c - 4)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(2c + 4)(2c - 4)$ is in the form of $(a + b)(a - b)$ , which is a difference of squares. $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(2c + 4)(2c - 4)$ with $(a + b)(a - b)$ . $a = 2c$ $b = 4$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(2c + 4)(2c - 4)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(2c + 4)(2c - 4) = (2c)^2 - 4^2$
Simplify Expression: Simplify $(2c)^2 - 4^2.$ $(2c)^2 - 4^2 = (2c \cdot 2c) - (4 \cdot 4)$ $= 4c^2 - 16$