Q. Find the numerical value of the log expression.loga=9logb=6logc=4loga9b5c5Answer:
Identify Given Logarithm Values: Identify the given logarithm values and the expression to evaluate.We are given that loga=9, logb=6, and logc=4. We need to find the numerical value of log(a9b5c5).
Apply Logarithm Properties: Apply the properties of logarithms to simplify the expression.First, we use the quotient rule of logarithms, which states that log(ba)=log(a)−log(b).log(a9b5c5)=log(b5c5)−log(a9)
Simplify Square Root: Simplify the square root and apply the power rule of logarithms.The power rule of logarithms states that log(ak)=k⋅log(a). The square root is equivalent to raising to the power of 21.log(b5c5)=log((b5c5)21)=21⋅log(b5c5)
Apply Product Rule: Apply the product rule of logarithms to the term inside the square root. The product rule of logarithms states that log(a⋅b)=log(a)+log(b). (21)⋅log(b5c5)=(21)⋅(log(b5)+log(c5))
Apply Power Rule: Apply the power rule to the logarithms of b and c.log(b5)=5×log(b) and log(c5)=5×log(c).21×(log(b5)+log(c5))=21×(5×log(b)+5×log(c))
Substitute Given Values: Substitute the given values of logb and logc into the expression.logb=6 and logc=4, so we substitute these values in.(1/2)×(5×log(b)+5×log(c))=(1/2)×(5×6+5×4)
Perform Arithmetic Operations: Perform the arithmetic operations.(21)×(5×6+5×4)=(21)×(30+20)=(21)×50=25
Apply Power Rule to Logarithm: Apply the power rule to the logarithm of a9. log(a9)=9×log(a) and substitute the given value of loga=9. log(a9)=9×9=81
Combine Results: Combine the results to find the final value of the original expression. log(a9b5c5)=25−81
Perform Final Subtraction: Perform the final subtraction to get the numerical value. 25−81=−56
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