Q. Find the numerical value of the log expression.loga=9logb=2logc=−6loga9b43c5Answer:
Apply Quotient Rule: Let's start by expressing the given logarithm using the properties of logarithms.We have log(a9b43c5).First, we apply the quotient rule of logarithms, which states that log(ba)=log(a)−log(b).
Rewrite as Difference: Now we rewrite the expression as a difference of two logarithms: log(3c5)−log(a9b4).
Apply Power Rule: Next, we apply the power rule of logarithms, which states that log(an)=nlog(a), to the terms inside the logarithms.For the first term, since 3c5 is the same as c35, we get log(c35)=35log(c).For the second term, we have two variables inside the logarithm, so we apply the product rule of logarithms, log(ab)=log(a)+log(b), before applying the power rule.
Apply Product Rule: Applying the product rule to the second term gives us log(a9)+log(b4). Now we apply the power rule to each of these terms to get 9log(a) and 4log(b).
Distribute Negative Sign: Our expression now looks like this:(35)log(c)−(9log(a)+4log(b)).We distribute the negative sign through the parenthesis to get:(35)log(c)−9log(a)−4log(b).
Substitute Given Values: Now we substitute the given values of loga, logb, and logc into the expression.This gives us (35)∗(−6)−9∗9−4∗2.
Perform Arithmetic Operations: We perform the arithmetic operations: 35×(−6)=−10, 9×9=81, and 4×2=8. So the expression simplifies to \$\(-10\) - \(81\) - \(8\)\$.
Find Numerical Value: Finally, we add the numbers together to find the numerical value of the expression: \(-10 - 81 - 8 = -99\).
More problems from Quotient property of logarithms