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Find the numerical value of the log expression.

{:[log a=9quad log b=2quad log c=-6],[log ((root(3)(c^(5)))/(a^(9)b^(4)))]:}
Answer:

Find the numerical value of the log expression.\newlineloga=9logb=2logc=6logc53a9b4 \begin{array}{c} \log a=9 \quad \log b=2 \quad \log c=-6 \\ \log \frac{\sqrt[3]{c^{5}}}{a^{9} b^{4}} \end{array} \newlineAnswer:

Full solution

Q. Find the numerical value of the log expression.\newlineloga=9logb=2logc=6logc53a9b4 \begin{array}{c} \log a=9 \quad \log b=2 \quad \log c=-6 \\ \log \frac{\sqrt[3]{c^{5}}}{a^{9} b^{4}} \end{array} \newlineAnswer:
  1. Apply Quotient Rule: Let's start by expressing the given logarithm using the properties of logarithms.\newlineWe have log(c53a9b4)\log \left(\frac{\sqrt[3]{c^{5}}}{a^{9}b^{4}}\right).\newlineFirst, we apply the quotient rule of logarithms, which states that log(ab)=log(a)log(b)\log\left(\frac{a}{b}\right) = \log(a) - \log(b).
  2. Rewrite as Difference: Now we rewrite the expression as a difference of two logarithms: log(c53)log(a9b4)\log(\sqrt[3]{c^{5}}) - \log(a^{9}b^{4}).
  3. Apply Power Rule: Next, we apply the power rule of logarithms, which states that log(an)=nlog(a)\log(a^n) = n\log(a), to the terms inside the logarithms.\newlineFor the first term, since c53\sqrt[3]{c^{5}} is the same as c53c^{\frac{5}{3}}, we get log(c53)=53log(c)\log(c^{\frac{5}{3}}) = \frac{5}{3}\log(c).\newlineFor the second term, we have two variables inside the logarithm, so we apply the product rule of logarithms, log(ab)=log(a)+log(b)\log(ab) = \log(a) + \log(b), before applying the power rule.
  4. Apply Product Rule: Applying the product rule to the second term gives us log(a9)+log(b4)\log(a^{9}) + \log(b^{4}). Now we apply the power rule to each of these terms to get 9log(a)9\log(a) and 4log(b)4\log(b).
  5. Distribute Negative Sign: Our expression now looks like this:\newline(53)log(c)(9log(a)+4log(b))(\frac{5}{3})\log(c) - (9\log(a) + 4\log(b)).\newlineWe distribute the negative sign through the parenthesis to get:\newline(53)log(c)9log(a)4log(b)(\frac{5}{3})\log(c) - 9\log(a) - 4\log(b).
  6. Substitute Given Values: Now we substitute the given values of loga\log a, logb\log b, and logc\log c into the expression.\newlineThis gives us (53)(6)9942(\frac{5}{3})*(-6) - 9*9 - 4*2.
  7. Perform Arithmetic Operations: We perform the arithmetic operations: 53×(6)=10\frac{5}{3}\times(-6) = -10, 9×9=819\times9 = 81, and 4×2=84\times2 = 8. So the expression simplifies to \$\(-10\) - \(81\) - \(8\)\$.
  8. Find Numerical Value: Finally, we add the numbers together to find the numerical value of the expression: \(-10 - 81 - 8 = -99\).

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