Q. Find the numerical value of the log expression.loga=8logb=1logc=−4logc3a5b4Answer:
Apply Quotient Rule: We are given the values of loga, logb, and logc, and we need to find the value of log(c3a5b4). Let's start by applying the quotient rule of logarithms, which states that log(yx)=log(x)−log(y).
Deal with Numerator: Now, we need to deal with the numerator and the denominator separately. For the numerator, which is a5b4, we can apply the product rule of logarithms, which states that log(xy)=log(x)+log(y). We also need to consider the exponents, using the power rule of logarithms, which states that log(xk)=k⋅log(x).
Deal with Denominator: Applying the product and power rules to the numerator, we get log(a5)+log(b4) which simplifies to 5log(a)+4log(b). Substituting the given values, we have 5×8+4×1, which equals 40+4=44.
Combine Results: For the denominator, we have c3, which can be rewritten as c23. Applying the power rule of logarithms, we get (23)log(c). Substituting the given value of logc, we have (23)(−4), which equals −6.
Combine Results: For the denominator, we have c3, which can be rewritten as c23. Applying the power rule of logarithms, we get (23)log(c). Substituting the given value of logc, we have (23)(−4), which equals −6.Now we can combine the results for the numerator and the denominator using the quotient rule we applied in the first step. We have log(c3a5b4)=log(a5b4)−log(c3) which simplifies to 44−(−6), giving us a final result of 44+6=50.
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