Q. Find the numerical value of the log expression.loga=7logb=4logc=6loga6c5b8Answer:
Apply Quotient Rule: Using the given values for loga, logb, and logc, we need to evaluate the expression log(a6c5b8). We can use the properties of logarithms to simplify the expression.First, apply the quotient rule of logarithms, which states that log(ba)=log(a)−log(b).\log\left(\frac{b^\(8\)}{a^\(6\)c^\(5\)}\right) = \log(b^\(8) - \log(a^6c^5)
Apply Product Rule: Next, apply the product rule of logarithms to the term log(a6c5), which states that log(ab)=log(a)+log(b).log(a6c5)=log(a6)+log(c5)
Apply Power Rule: Now, apply the power rule of logarithms to each term, which states that log(an)=nlog(a).log(b8)=8log(b)log(a6)=6log(a)log(c5)=5log(c)
Substitute Given Values: Substitute the given values for loga, logb, and logc into the expression.log(b8)−(log(a6)+log(c5))=8⋅log(b)−(6⋅log(a)+5⋅log(c))=8⋅4−(6⋅7+5⋅6)
Perform Arithmetic Operations: Perform the arithmetic operations.=32−(42+30)=32−72=−40
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