Q. Find the numerical value of the log expression.loga=4logb=−8logc=−3logc5a3b5Answer:
Identify Given Values: Identify the given logarithmic values and the expression to be evaluated.We are given:loga=4logb=−8logc=−3We need to find the value of log(c5a3b5).
Apply Logarithmic Properties: Apply the properties of logarithms to the expression.Using the quotient rule of logarithms, which states that log(yx)=log(x)−log(y), we can write:log(c5a3b5)=log(a3b5)−log(c5)
Apply Power Rule: Apply the power rule of logarithms to the expression inside the square root.The power rule states that log(xk)=k⋅log(x). Since we have a square root, which is equivalent to the power of 21, we can write:log(a3b5)=(21)⋅log(a3b5)
Apply Product Rule: Apply the product rule of logarithms to the expression inside the logarithm.The product rule states that log(xy)=log(x)+log(y). Therefore:(21)⋅log(a3b5)=(21)⋅(log(a3)+log(b5))
Apply Power Rule: Apply the power rule to the individual logarithms.log(a3)=3⋅log(a)log(b5)=5⋅log(b)So, (1/2)⋅(log(a3)+log(b5))=(1/2)⋅(3⋅log(a)+5⋅log(b))
Substitute Given Values: Substitute the given values of loga and logb into the expression.loga=4 and logb=−8, so:21×(3×log(a)+5×log(b))=21×(3×4+5×(−8))