Q. Find the numerical value of the log expression.loga=3logb=9logc=−2logc63a5b5Answer:
Apply Properties of Logarithms: Apply the properties of logarithms to the given expression.We have the expression log(c63a5b5). We can use the quotient rule of logarithms, which states that log(BA)=log(A)−log(B), and the power rule of logarithms, which states that log(An)=n⋅log(A), to simplify this expression.
Apply Quotient Rule: Apply the quotient rule to the expression.Using the quotient rule, we get:log(3a5b5)−log(c6).
Apply Power Rule: Apply the power rule to the expression.The cube root can be expressed as a power of 31, so we can rewrite the expression as:log((a5b5)31)−log(c6).Now, applying the power rule, we get:31log(a5)+31log(b5)−6log(c).
Apply Power Rule Again: Apply the power rule again to the individual logarithms.We can further simplify the expression by applying the power rule to log(a5) and log(b5):35log(a)+35log(b)−6log(c).
Substitute Given Values: Substitute the given values of log(a), log(b), and log(c) into the expression.We are given that log(a)=3, log(b)=9, and log(c)=−2. Substituting these values, we get:35⋅3+35⋅9−6⋅(−2).
Perform Arithmetic Operations: Perform the arithmetic operations.Now we calculate the numerical value:35⋅3=5,35⋅9=15,−6⋅(−2)=12.Adding these together, we get:5+15+12=32.
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