Q. Find the numerical value of the log expression.loga=2logb=5logc=−8loga3c5b5Answer:
Apply Quotient Rule: Let's start by expressing the given logarithm using the properties of logarithms.We have the expression log(a3c5b5).Using the quotient rule of logarithms, which states that log(ba)=log(a)−log(b), we can separate the numerator and the denominator.
Convert Square Root to Exponent: Now, we focus on the denominator, which contains a square root. The square root can be expressed as an exponent of 21. So, a3c5 can be written as (a3c5)21. Using the power rule of logarithms, which states that log(an)=nlog(a), we can take the exponent outside the logarithm.
Apply Power Rule: Applying the power rule to both the numerator and the denominator, we get: log(b5)−log((a3c5)21). This simplifies to 5log(b)−(21)log(a3c5).
Apply Product Rule: Next, we apply the product rule of logarithms, which states that log(a⋅b)=log(a)+log(b), to the term log(a3c5). This gives us:(21)⋅(log(a3)+log(c5)).
Apply Power Rule Again: Now, we apply the power rule again to the terms log(a3) and log(c5), which gives us: (21)⋅(3⋅log(a)+5⋅log(c)).
Substitute Given Values: Substituting the given values of loga, logb, and logc into the expression, we get:5⋅log(b)−(21)⋅(3⋅log(a)+5⋅log(c)) becomes 5⋅5−(21)⋅(3⋅2+5⋅(−8)).
Perform Arithmetic Operations: Performing the arithmetic operations, we have: 25−(21)∗(6−40) which simplifies to 25−(21)∗(−34).
Calculate Final Value: Finally, we calculate the value of the expression: 25−(21)∗(−34)=25−(−17)=25+17=42.
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