Q. Find the numerical value of the log expression.loga=2logb=2logc=2loga9b5c7Answer:
Apply Rules: Using the quotient and power rules of logarithms, we can expand the given expression.Quotient rule of logarithm: log(ba)=log(a)−log(b)Power rule of logarithm: log(an)=n⋅log(a)Let's apply these rules to the given expression log(a9b5c7).
Separate Numerator and Denominator: First, apply the quotient rule to separate the logarithm of the numerator and the denominator:log(a9b5c7)=log(c7)−log(a9b5)
Apply Product Rule: Next, apply the product rule to the logarithm in the denominator:Product rule of logarithm: log(a×b)=log(a)+log(b)log(a9b5)=log(a9)+log(b5)
Apply Power Rule: Now, apply the power rule to each logarithm:log(c7)=7⋅log(c)log(a9)=9⋅log(a)log(b5)=5⋅log(b)
Substitute Given Values: Substitute the given values for loga, logb, and logc into the expression:7×log(c)−(9×log(a)+5×log(b))7×2−(9×2+5×2)
Perform Arithmetic Operations: Perform the arithmetic operations:14−(18+10)14−28
Calculate Final Result: Calculate the final result: 14−28=−14
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