Q. Find the numerical value of the log expression.loga=1log3b7c4a4logb=6logc=9Answer:
Identify Given Values: Identify the given logarithmic values and the expression to be evaluated.We are given loga=1, logb=6, and logc=9. We need to find the value of log(3b7c4a4).
Apply Power Rule: Apply the logarithm power rule to the numerator of the expression.The power rule of logarithms states that log(an)=n⋅log(a). Therefore, log(a4)=4⋅log(a).Since loga=1, we have log(a4)=4⋅1=4.
Apply Power Rule to Denominator: Apply the logarithm power rule to the denominator of the expression.We have a cube root in the denominator, which can be written as a power of 31. The expression inside the cube root is b7c4, which can be separated using the product rule of logarithms: log(b7c4)=log(b7)+log(c4).Now apply the power rule: log(b7)=7⋅log(b) and log(c4)=4⋅log(c).Since logb=6 and logc=9, we have log(b7)=7⋅6=42 and log(c4)=4⋅9=36.
Combine Denominator Logarithms: Combine the logarithms of the denominator and apply the cube root.We have log(b7)+log(c4)=42+36=78.Now, we need to apply the cube root, which is the same as multiplying by 1/3: (1/3)×log(b7c4)=(1/3)×78=26.
Use Quotient Rule: Use the quotient rule of logarithms to combine the numerator and denominator.The quotient rule of logarithms states that log(ba)=log(a)−log(b). We have log(a4)−log(3b7c4)=4−26.
Calculate Final Value: Calculate the final numerical value.Subtract the value found for the denominator from the numerator: 4−26=−22.
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