Q. Find the numerical value of the log expression.loga=11logb=−7logc=−12loga9b63cAnswer:
Given Log Values: We are given the values of loga=11, logb=−7, and logc=−12. We need to find the value of log(a9b63c).First, let's apply the logarithm rules to simplify the expression.Using the quotient rule of logarithms, which states that log(yx)=logx−logy, we can write:log(a9b63c)=log(3c)−log(a9b6).
Simplify Expression: Next, we apply the power rule of logarithms, which states that log(xn)=n⋅logx, to the terms a9 and b6:log(a9)=9⋅loga and log(b6)=6⋅logb.We also apply the same rule to 3c, which can be written as c1/3, so log(3c)=31⋅logc.
Apply Log Rules: Now, we substitute the given logarithm values into the expression:log(3c)−log(a9b6) becomes 31⋅logc−(9⋅loga+6⋅logb).Substituting the values, we get 31⋅(−12)−(9⋅11+6⋅(−7)).
Substitute Values: Let's perform the calculations:31⋅(−12)=−4,9⋅11=99,and 6⋅(−7)=−42.So, the expression becomes −4−(99−42).
Perform Calculations: Finally, we calculate the remaining operation:−4−(99−42)=−4−99+42=−4−57=−61.Therefore, the numerical value of the log expression is −61.
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