Find the numerical answer to the summation given below. sum_(n=0)^(92)(6n+3) Answer:

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Find the numerical answer to the summation given below.  sum_(n=0)^(92)(6n+3) Answer:

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Recognize arithmetic series: To solve the summation, we need to recognize that it is the sum of an arithmetic series. The general formula for the sum of an arithmetic series is S = (n/2)(a_1 + a_n), where n is the number of terms, a_1 is the first term, and a_n is the last term. First, we need to find the number of terms in the series.Find number of terms: The series starts at n=0 and ends at n=92, so the number of terms is 92 - 0 + 1 = 93 terms.Find first term: Next, we need to find the first term of the series when n=0. Plugging n=0 into the formula 6n+3 gives us the first term: a_1 = 6(0) + 3 = 3.Find last term: Now, we need to find the last term of the series when n=92. Plugging n=92 into the formula 6n+3 gives us the last term: a_n = 6(92) + 3 = 552 + 3 = 555.Use sum formula: We can now use the sum formula for an arithmetic series: S = (n/2)(a_1 + a_n). Plugging in the values we have: S = (93/2)(3 + 555).Perform calculation: Perform the calculation inside the parentheses first: 3 + 555 = 558.Multiply by number of terms: Now multiply this sum by the number of terms divided by 2: S = (93/2) * 558.Perform final calculation: Perform the multiplication to find the sum: S = 46.5 * 558.Finally, calculate the product to get the numerical answer: S = 25947.

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=0}^{92}(6 n+3)$ $\newline$ Answer:

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Find the numerical answer to the summation given below.\newline∑n=092(6n+3) \sum_{n=0}^{92}(6 n+3) n=0∑92​(6n+3)\newlineAnswer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=0}^{92}(6 n+3)$ $\newline$ Answer: