Find the numerical answer to the summation given below. sum_(n=1)^(95)(2n+1) Answer:

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Find the numerical answer to the summation given below.  sum_(n=1)^(95)(2n+1) Answer:

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Identify Arithmetic Series: To solve the summation of the sequence, we need to find the sum of the arithmetic series. The given series is an arithmetic series because each term increases by a constant difference, which is 2 in this case. The first term of the series when n=1 is 2(1) + 1 = 3, and the last term when n=95 is 2(95) + 1 = 191. The sum of an arithmetic series can be found using the formula S = n/2 * (a_1 + a_n), where S is the sum of the series, n is the number of terms, a_1 is the first term, and a_n is the last term.Determine Number of Terms: First, we need to determine the number of terms in the series. Since the series starts at n=1 and ends at n=95, there are 95 terms in total.Apply Sum Formula: Now we can use the sum formula for an arithmetic series: S = n/2 * (a_1 + a_n). Plugging in the values we have S = 95/2 * (3 + 191).Calculate First and Last Term: Perform the calculation inside the parentheses first: 3 + 191 = 194.Perform Multiplication: Now multiply the number of terms divided by 2 with the sum of the first and last term: S = 95/2 * 194.Find the Sum: Calculate the multiplication: S = 47.5 * 194.Perform the multiplication to find the sum: S = 9215.

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=1}^{95}(2 n+1)$ $\newline$ Answer:

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Find the numerical answer to the summation given below.\newline∑n=195(2n+1) \sum_{n=1}^{95}(2 n+1) n=1∑95​(2n+1)\newlineAnswer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=1}^{95}(2 n+1)$ $\newline$ Answer: