Find the inverse of the function. y = 5x + 1 Write your answer in the form ax + b. Simplify any fractions. y = ______

Swap x and y: To find the inverse of the function, we first swap x and y. This gives us the equation x = 5y + 1.Solve for y: Next, we need to solve for y. To do this, we subtract 1 from both sides of the equation to isolate the term with y. This gives us x - 1 = 5y + 1 - 1.Isolate y: Simplifying the equation, we get x - 1 = 5y. Now we need to isolate y by dividing both sides of the equation by 5.Final result: Dividing both sides by 5 gives us (x - 1)/5 = y, or y = (1/5)x - 1/5.

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Find the inverse of the function. $\newline$ $y = 5x + 1$ $\newline$ Write your answer in the form $ax + b$ . Simplify any fractions. $\newline$ y = ______

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Algebra 1

Find the inverse of a linear function

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Q. Find the inverse of the function.

\newline

y = 5x + 1

\newline

Write your answer in the form

ax + b

. Simplify any fractions.

\newline

y = ______

Swap $x$ and $y$ : To find the inverse of the function, we first swap $x$ and $y$ . This gives us the equation $x = 5y + 1$ .
Solve for $y$ : Next, we need to solve for $y$ . To do this, we subtract $1$ from both sides of the equation to isolate the term with $y$ . This gives us $x - 1 = 5y + 1 - 1$ .
Isolate y: Simplifying the equation, we get $x - 1 = 5y$ . Now we need to isolate $y$ by dividing both sides of the equation by $5$ .
Final result: Dividing both sides by $5$ gives us $(x - 1)/5 = y$ , or $y = (1/5)x - 1/5$ .