Find the inverse laplace transform of (s²- 4s - 5)/(s² -4s-5)

Simplify the function: The given function is (s² - 4s - 5)/(s² - 4s - 5). To find the inverse Laplace transform, we first simplify the function. Calculation: (s² - 4s - 5)/(s² - 4s - 5) simplifies to 1, since the numerator and denominator are identical.Find inverse Laplace transform: Now that we have the simplified function, which is 1, we can find the inverse Laplace transform of 1. The inverse Laplace transform of 1 is the delta function, δ(t), which represents an impulse at time t = 0.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the inverse laplace transform of $(s^2- 4s - 5)/(s^2 -4s-5)$

View step-by-step help

Home

Math Problems

Precalculus

Complex conjugate theorem

Full solution

Q. Find the inverse laplace transform of

(s^2- 4s - 5)/(s^2 -4s-5)

Simplify the function: The given function is $(s^2 - 4s - 5)/(s^2 - 4s - 5)$ . To find the inverse Laplace transform, we simplify the function. $\newline$ Calculation: $(s^2 - 4s - 5)/(s^2 - 4s - 5)$ simplifies to $1$ , since the numerator and denominator are identical.
Find inverse Laplace transform: Now that we have the simplified function, which is $1$ , we can find the inverse Laplace transform of $1$ . The inverse Laplace transform of $1$ is the delta function, $\delta(t)$ , which represents an impulse at time $t = 0$ .