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Find the instantaneous rate of change of $g(x) = -2$ at $x = 19$ . $\newline$ Write your answer as an integer or a fractions" target="_blank" class="backlink">fraction. Simplify any fractions.

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Find instantaneous rates of change

Full solution

Q. Find the instantaneous rate of change of

g(x) = -2

at

x = 19

.

\newline

Write your answer as an integer or a fraction. Simplify any fractions.

Identify Function Type: Identify the type of function and the need for differentiation. $\newline$ Since $g(x) = -2$ is a constant function, its derivative, which represents the instantaneous rate of change, is always $0$ .
Calculate Derivative: Calculate the derivative of $g(x)$ . The derivative of a constant is $0$ . Therefore, $g'(x) = 0$ .

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