Find the fifth term of the geometric sequence 7,-14,28,dots a_(5)=◻

Identify Common Ratio: To find the fifth term of a geometric sequence, we need to identify the common ratio (r) of the sequence. The common ratio is found by dividing any term by the previous term. Let's divide the second term by the first term to find the common ratio: r = (-14) / 7 = -2.Find Fifth Term: Now that we have the common ratio, we can find the fifth term (a_5) using the formula for the nth term of a geometric sequence: a_n = a_1 * r^(n-1), where a_1 is the first term and n is the term number. Let's plug in the values to find a_5: a_5 = 7 * (-2)^(5-1) = 7 * (-2)^4.Calculate Common Ratio: Calculate the value of (-2)^4: (-2)^4 = 16.Multiply First Term: Now, multiply the first term by the value we just calculated: a_5 = 7 * 16 = 112.

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Q. Find the fifth term of the geometric sequence

7,-14,28, \ldots

\newline

\mathrm{a}_{5}=\square

Identify Common Ratio: To find the fifth term of a geometric sequence, we need to identify the common ratio $r$ of the sequence. The common ratio is found by dividing any term by the previous term. $\newline$ Let's divide the second term by the first term to find the common ratio: $r = (-14) / 7 = -2$ .
Find Fifth Term: Now that we have the common ratio, we can find the fifth term $a_5$ using the formula for the nth term of a geometric sequence: $a_n = a_1 \cdot r^{(n-1)}$ , where $a_1$ is the first term and $n$ is the term number. $\newline$ Let's plug in the values to find $a_5$ : $a_5 = 7 \cdot (-2)^{5-1} = 7 \cdot (-2)^4$ .
Calculate Common Ratio: Calculate the value of $(-2)^4$ : $(-2)^4 = 16$ .
Multiply First Term: Now, multiply the first term by the value we just calculated: $a_5 = 7 \times 16 = 112$ .