Find the distance between the two points. (8,-8) and (-5.2,-8)

Calculate Differences: Calculate the difference in the x-coordinates (Δx) and y-coordinates (Δy). Δx = -5.2 - 8 = -13.2 Δy = -8 - (-8) = 0Use Distance Formula: Use the distance formula: distance = sqrt(Δx^2 + Δy^2). distance = sqrt((-13.2)^2 + 0^2)Calculate Squares: Calculate the squares and sum them up. distance = sqrt(174.24 + 0)Simplify Square Root: Simplify the square root. distance = sqrt(174.24) distance = 13.2

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Find the distance between the two points. $\newline$ $(8,-8)$ and $(-5.2,-8)$ $\newline$

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Precalculus

Find the magnitude of a three-dimensional vector

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Q. Find the distance between the two points.

\newline

(8,-8)

and

(-5.2,-8)

\newline

Calculate Differences: Calculate the difference in the x-coordinates ( $\Delta x$ ) and y-coordinates ( $\Delta y$ ). $\newline$ $\Delta x = -5.2 - 8 = -13.2$ $\newline$ $\Delta y = -8 - (-8) = 0$
Use Distance Formula: Use the distance formula: $\text{distance} = \sqrt{\Delta x^2 + \Delta y^2}$ . $\newline$ $\text{distance} = \sqrt{(-13.2)^2 + 0^2}$
Calculate Squares: Calculate the squares and sum them up. $\newline$ $\text{distance} = \sqrt{174.24 + 0}$
Simplify Square Root: Simplify the square root. $\newline$ distance = $\sqrt{174.24}$ $\newline$ distance = $13.2$