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Let’s check out your problem:
Find the distance between the points
(
3
,
4
)
(3,4)
(
3
,
4
)
and
(
10
,
4
)
(10,4)
(
10
,
4
)
.
\newline
____ units
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Math Problems
Precalculus
Find the magnitude of a three-dimensional vector
Full solution
Q.
Find the distance between the points
(
3
,
4
)
(3,4)
(
3
,
4
)
and
(
10
,
4
)
(10,4)
(
10
,
4
)
.
\newline
____ units
Calculate Coordinates Difference:
Calculate the difference in
x
x
x
-coordinates and
y
y
y
-coordinates between the two points.
\newline
x
2
−
x
1
=
10
−
3
=
7
x_2 - x_1 = 10 - 3 = 7
x
2
−
x
1
=
10
−
3
=
7
\newline
y
2
−
y
1
=
4
−
4
=
0
y_2 - y_1 = 4 - 4 = 0
y
2
−
y
1
=
4
−
4
=
0
Use Distance Formula:
Use the
distance formula
:
Distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
Distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
.
\newline
Distance
=
(
7
)
2
+
(
0
)
2
\text{Distance} = \sqrt{(7)^2 + (0)^2}
Distance
=
(
7
)
2
+
(
0
)
2
\newline
Distance
=
49
+
0
\text{Distance} = \sqrt{49 + 0}
Distance
=
49
+
0
\newline
Distance
=
49
\text{Distance} = \sqrt{49}
Distance
=
49
\newline
Distance
=
7
\text{Distance} = 7
Distance
=
7
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\newline
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Find the distance between
P
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P
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4
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and
Q
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Q(9,7)
Q
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\newline
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P
P
P
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Q
Q
Q
is
□
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□
.
\newline
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x
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6
6
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y
3
3 x^{2} y^{3}
3
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y
3
and
6
x
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y
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6 x^{3} y^{2}
6
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2
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