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Find the distance between the points $(2,7)$ and $(8,7)$ . $\newline$ ____ units

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Find the magnitude of a three-dimensional vector

Full solution

Q. Find the distance between the points

(2,7)

and

(8,7)

.

\newline

____ units

Calculate Differences: Calculate the differences in the $x$ -coordinates and $y$ -coordinates of the two points. $x_2 - x_1 = 8 - 2 = 6$ $y_2 - y_1 = 7 - 7 = 0$
Apply Distance Formula: Apply the distance formula: $distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ . $\newline$ $distance = \sqrt{6^2 + 0^2}$ $\newline$ $distance = \sqrt{36}$ $\newline$ $distance = 6$

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