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Let’s check out your problem:
Find the distance between the points
(
2
,
6
)
(2,6)
(
2
,
6
)
and
(
10
,
6
)
(10,6)
(
10
,
6
)
.
\newline
_
_
_
_
\_\_\_\_
____
units
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Math Problems
Precalculus
Find the magnitude of a three-dimensional vector
Full solution
Q.
Find the distance between the points
(
2
,
6
)
(2,6)
(
2
,
6
)
and
(
10
,
6
)
(10,6)
(
10
,
6
)
.
\newline
_
_
_
_
\_\_\_\_
____
units
Calculate Coordinates Difference:
Calculate the difference in
x
x
x
-coordinates and
y
y
y
-coordinates between the two points.
\newline
x
2
−
x
1
=
10
−
2
=
8
x_2 - x_1 = 10 - 2 = 8
x
2
−
x
1
=
10
−
2
=
8
\newline
y
2
−
y
1
=
6
−
6
=
0
y_2 - y_1 = 6 - 6 = 0
y
2
−
y
1
=
6
−
6
=
0
Apply Distance Formula:
Apply the
distance formula
:
distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
.
distance
=
(
8
)
2
+
(
0
)
2
\text{distance} = \sqrt{(8)^2 + (0)^2}
distance
=
(
8
)
2
+
(
0
)
2
distance
=
64
+
0
\text{distance} = \sqrt{64 + 0}
distance
=
64
+
0
distance
=
64
\text{distance} = \sqrt{64}
distance
=
64
distance
=
8
\text{distance} = 8
distance
=
8
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Rewrite in simplest terms:
6
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(
−
2
c
−
9
)
6 c-9(-2 c-9)
6
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)
\newline
Answer:
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y
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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an
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\newline
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Write the equation of the line that passes through the points
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−
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4
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(-1,-4)
(
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4
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\newline
Answer:
\newline
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Find the distance between
P
(
4
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P(4,4)
P
(
4
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and
Q
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7
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Q(9,7)
Q
(
9
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7
)
.
\newline
The distance between
P
P
P
and
Q
Q
Q
is
□
\square
□
.
\newline
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Question
x
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(
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)
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6
6
6
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3
x
2
y
3
3 x^{2} y^{3}
3
x
2
y
3
and
6
x
3
y
2
6 x^{3} y^{2}
6
x
3
y
2
. Find its and area.
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77
77
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269
269
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2
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