Find the discriminant. s^2 + 3s + 4 = 0 ____

Identify Coefficients: Identify the coefficients of the quadratic equation. The standard form of a quadratic equation is ax^2 + bx + c = 0. By comparing this with the given equation s^2 + 3s + 4 = 0, we can identify the coefficients as follows: a = 1 (coefficient of s^2) b = 3 (coefficient of s) c = 4 (constant term)Calculate Discriminant: Calculate the discriminant using the formula D = b^2 - 4ac. Substitute the identified values into the discriminant formula: D = b^2 - 4ac D = (3)^2 - 4(1)(4)Perform Calculations: Perform the calculations to find the value of the discriminant. D = 9 - 4(1)(4) D = 9 - 16 D = -7

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Find the discriminant. $\newline$ $s^2 + 3s + 4 = 0$

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Algebra 1

Using the discriminant

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Q. Find the discriminant.

\newline

s^2 + 3s + 4 = 0

Identify Coefficients: Identify the coefficients of the quadratic equation. $\newline$ The standard form of a quadratic equation is $ax^2 + bx + c = 0$ . By comparing this with the given equation $s^2 + 3s + 4 = 0$ , we can identify the coefficients as follows: $\newline$ $a = 1$ (coefficient of $s^2$ ) $\newline$ $b = 3$ (coefficient of $s$ ) $\newline$ $c = 4$ (constant term)
Calculate Discriminant: Calculate the discriminant using the formula $D = b^2 - 4ac$ . $\newline$ Substitute the identified values into the discriminant formula: $\newline$ $D = b^2 - 4ac$ $\newline$ $D = (3)^2 - 4(1)(4)$
Perform Calculations: Perform the calculations to find the value of the discriminant. $\newline$ $D = 9 - 4(1)(4)$ $\newline$ $D = 9 - 16$ $\newline$ $D = -7$