Find the discriminant. 5x^2 + x + 1 = 0 ____

Identify coefficients: Identify the coefficients of the quadratic equation. The quadratic equation is in the form ax^2 + bx + c = 0. For the equation 5x^2 + x + 1 = 0, the coefficients are: a = 5 b = 1 c = 1Use discriminant formula: Use the discriminant formula. The discriminant D of a quadratic equation ax^2 + bx + c = 0 is given by D = b^2 - 4ac. We will substitute the identified values of a, b, and c into this formula.Calculate discriminant: Calculate the discriminant. Substitute a = 5, b = 1, and c = 1 into the formula D = b^2 - 4ac. D = (1)^2 - 4 * 5 * 1 D = 1 - 20 D = -19

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the discriminant. $\newline$ $5x^2 + x + 1 = 0$

View step-by-step help

Home

Math Problems

Algebra 1

Using the discriminant

Full solution

Q. Find the discriminant.

\newline

5x^2 + x + 1 = 0

Identify coefficients: Identify the coefficients of the quadratic equation. $\newline$ The quadratic equation is in the form $ax^2 + bx + c = 0$ . For the equation $5x^2 + x + 1 = 0$ , the coefficients are: $\newline$ a = $5$ $\newline$ b = $1$ $\newline$ c = $1$
Use discriminant formula: Use the discriminant formula. $\newline$ The discriminant $D$ of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$ . We will substitute the identified values of $a$ , $b$ , and $c$ into this formula.
Calculate discriminant: Calculate the discriminant. $\newline$ Substitute $a = 5$ , $b = 1$ , and $c = 1$ into the formula $D = b^2 - 4ac$ . $\newline$ $D = (1)^2 - 4 \times 5 \times 1$ $\newline$ $D = 1 - 20$ $\newline$ $D = -19$