Find the discriminant. 5s^2 + 6s - 1 = 0 ____

Identify coefficients: Identify the coefficients a, b, and c from the quadratic equation 5s^2 + 6s - 1 = 0 by comparing it to the standard form ax^2 + bx + c = 0. In this case, a = 5, b = 6, and c = -1.Recall discriminant formula: Recall the formula for the discriminant of a quadratic equation, which is D = b^2 - 4ac.Substitute values: Substitute the identified values into the discriminant formula: D = 6^2 - 4 * 5 * (-1).Calculate discriminant: Calculate the discriminant: D = 36 - 4 * 5 * (-1) = 36 + 20 = 56.

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Find the discriminant. $\newline$ $5s^2 + 6s - 1 = 0$

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Algebra 1

Using the discriminant

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Q. Find the discriminant.

\newline

5s^2 + 6s - 1 = 0

Identify coefficients: Identify the coefficients $a$ , $b$ , and $c$ from the quadratic equation $5s^2 + 6s - 1 = 0$ by comparing it to the standard form $ax^2 + bx + c = 0$ . In this case, $a = 5$ , $b = 6$ , and $c = -1$ .
Recall discriminant formula: Recall the formula for the discriminant of a quadratic equation, which is $D = b^2 - 4ac$ .
Substitute values: Substitute the identified values into the discriminant formula: $D = 6^2 - 4 \times 5 \times (-1)$ .
Calculate discriminant: Calculate the discriminant: $D = 36 - 4 \times 5 \times (-1) = 36 + 20 = 56$ .