Find the discriminant. 4s^2 + 8s + 4 = 0 ____

Identify values: Identify the values of a, b, and c from the quadratic equation in the form ax^2 + bx + c = 0. Comparing 4s^2 + 8s + 4 = 0 with ax^2 + bx + c = 0, we find: a = 4 b = 8 c = 4Use discriminant formula: Use the discriminant formula D = b^2 - 4ac to find the discriminant of the quadratic equation. Substitute 4 for a, 8 for b, and 4 for c in the formula. D = (8)^2 - 4 * 4 * 4Calculate discriminant: Calculate the discriminant. D = 64 - 4 * 4 * 4 D = 64 - 64 D = 0

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Find the discriminant. $\newline$ $4s^2 + 8s + 4 = 0$

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Algebra 1

Using the discriminant

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Q. Find the discriminant.

\newline

4s^2 + 8s + 4 = 0

Identify values: Identify the values of $a$ , $b$ , and $c$ from the quadratic equation in the form $ax^2 + bx + c = 0$ . Comparing $4s^2 + 8s + 4 = 0$ with $ax^2 + bx + c = 0$ , we find: $a = 4$ $b = 8$ $c = 4$
Use discriminant formula: Use the discriminant formula $D = b^2 - 4ac$ to find the discriminant of the quadratic equation. $\newline$ Substitute $4$ for $a$ , $8$ for $b$ , and $4$ for $c$ in the formula. $\newline$ $D = (8)^2 - 4 \times 4 \times 4$
Calculate discriminant: Calculate the discriminant. $\newline$ $D = 64 - 4 \times 4 \times 4$ $\newline$ $D = 64 - 64$ $\newline$ $D = 0$