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Find the derivative of the following function.

y=log_(8)(7x^(5)-8x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=log8(7x58x4) y=\log _{8}\left(7 x^{5}-8 x^{4}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=log8(7x58x4) y=\log _{8}\left(7 x^{5}-8 x^{4}\right) \newlineAnswer: y= y^{\prime}=
  1. Apply Change of Base Formula: To find the derivative of the function y=log8(7x58x4)y = \log_{8}(7x^5 - 8x^4), we will use the change of base formula for logarithms and the chain rule for differentiation.\newlineChange of base formula: logab=logcblogca\log_{a}b = \frac{\log_{c}b}{\log_{c}a}\newlineWe will use the natural logarithm (base ee) for this purpose.\newliney=log8(7x58x4)y = \log_{8}(7x^5 - 8x^4) can be rewritten as y=ln(7x58x4)ln(8)y = \frac{\ln(7x^5 - 8x^4)}{\ln(8)}
  2. Use Chain Rule for Differentiation: Now we need to differentiate the function with respect to xx using the chain rule.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.\newlineLet u=7x58x4u = 7x^5 - 8x^4, then y=ln(u)ln(8)y = \frac{\ln(u)}{\ln(8)}\newlineThe derivative of ln(u)\ln(u) with respect to uu is 1u\frac{1}{u}, and we need to multiply this by the derivative of uu with respect to xx.
  3. Find Derivative of Inner Function: Let's find the derivative of u=7x58x4u = 7x^5 - 8x^4 with respect to xx. Using the power rule, the derivative of xnx^n with respect to xx is nx(n1)n\cdot x^{(n-1)}. The derivative of 7x57x^5 is 35x435x^4 and the derivative of 8x4-8x^4 is 32x3-32x^3. So, the derivative of uu with respect to xx is xx11.
  4. Apply Chain Rule to Find Derivative: Now we can apply the chain rule to find the derivative of yy.y=1ududx/ln(8)y' = \frac{1}{u} \cdot \frac{du}{dx} / \ln(8)Substitute u=7x58x4u = 7x^5 - 8x^4 and dudx=35x432x3\frac{du}{dx} = 35x^4 - 32x^3 into the equation.y=1(7x58x4)(35x432x3)ln(8)y' = \frac{1}{(7x^5 - 8x^4)} \cdot \frac{(35x^4 - 32x^3)}{\ln(8)}
  5. Simplify the Derivative: Finally, we simplify the expression for the derivative.\newliney=35x432x3(7x58x4)ln(8)y' = \frac{35x^4 - 32x^3}{(7x^5 - 8x^4) \cdot \ln(8)}\newlineThis is the derivative of the function y=log8(7x58x4)y = \log_{8}(7x^5 - 8x^4) with respect to xx.

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