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Find the derivative of the following function.

y=log_(7)(9x^(6))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=log7(9x6) y=\log _{7}\left(9 x^{6}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=log7(9x6) y=\log _{7}\left(9 x^{6}\right) \newlineAnswer: y= y^{\prime}=
  1. Understand function and derivative: Understand the function and the type of derivative to find.\newlineWe need to find the derivative of the function yy with respect to xx, where yy is a logarithm with base 77 of the function 9x69x^6. We will use the chain rule and the formula for the derivative of a logarithm with an arbitrary base.
  2. Apply chain rule and formula: Apply the chain rule and the logarithmic derivative formula. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. The derivative of logb(u)\log_b(u) with respect to uu is 1uln(b)\frac{1}{u \cdot \ln(b)}, where bb is the base of the logarithm and ln\ln is the natural logarithm.
  3. Calculate inner function derivative: Calculate the derivative of the inner function 9x69x^6 with respect to xx. The inner function is 9x69x^6, and its derivative with respect to xx is 54x554x^5 (using the power rule: ddx[axn]=nax(n1)\frac{d}{dx} [ax^n] = n\cdot ax^{(n-1)}).
  4. Combine using chain rule: Combine the results using the chain rule.\newlineThe derivative of yy with respect to xx is the derivative of the outer function (log7(u)\log_7(u)) times the derivative of the inner function (9x69x^6). Using the formula from Step 22 and the result from Step 33, we get:\newliney=19x6ln(7)54x5y' = \frac{1}{9x^6 \cdot \ln(7)} \cdot 54x^5
  5. Simplify the expression: Simplify the expression.\newlineWe can simplify the expression by canceling out an x5x^5 from the numerator and denominator, and simplifying the constants:\newliney=549ln(7)x56y' = \frac{54}{9 \cdot \ln(7)} \cdot x^{5-6}\newliney=6ln(7)x1y' = \frac{6}{\ln(7)} \cdot x^{-1}\newliney=6x1ln(7)y' = \frac{6x^{-1}}{\ln(7)}

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