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Find the derivative of the following function.

y=log_(6)(-6x^(5)-6x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=log6(6x56x4) y=\log _{6}\left(-6 x^{5}-6 x^{4}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=log6(6x56x4) y=\log _{6}\left(-6 x^{5}-6 x^{4}\right) \newlineAnswer: y= y^{\prime}=
  1. Identify Function and Derivative: Identify the function and the type of derivative to be found.\newlineWe are given the function y=log6(6x56x4)y=\log_6(-6x^5-6x^4) and we need to find its derivative with respect to xx.
  2. Apply Chain Rule for Logarithmic Differentiation: Apply the chain rule for logarithmic differentiation.\newlineThe chain rule states that the derivative of logb(u(x))\log_b(u(x)) is (1/u(x))(du/dx)(1/u(x)) \cdot (du/dx), where bb is the base of the logarithm and u(x)u(x) is the function inside the logarithm.
  3. Differentiate Inside Function: Differentiate the inside function 6x56x4-6x^5-6x^4 with respect to xx. The derivative of 6x5-6x^5 is 30x4-30x^4 and the derivative of 6x4-6x^4 is 24x3-24x^3. So, the derivative of the inside function is 30x424x3-30x^4 - 24x^3.
  4. Apply Change of Base Formula: Apply the change of base formula for logarithms. The change of base formula is logb(a)=logc(a)logc(b)\log_b(a) = \frac{\log_c(a)}{\log_c(b)}, where cc is a new base. We can use the natural logarithm (base ee) for this purpose. So, y=log6(6x56x4)y=\log_6(-6x^5-6x^4) can be rewritten as y=ln(6x56x4)ln(6)y=\frac{\ln(-6x^5-6x^4)}{\ln(6)}.
  5. Differentiate Using Quotient Rule: Differentiate yy with respect to xx using the quotient rule.\newlineThe quotient rule is (v(dudx)u(dvdx))/v2(v \cdot (\frac{du}{dx}) - u \cdot (\frac{dv}{dx})) / v^2, where uu is the numerator and vv is the denominator.\newlineHere, u=ln(6x56x4)u = \ln(-6x^5-6x^4) and v=ln(6)v = \ln(6). Since ln(6)\ln(6) is a constant, its derivative dvdx\frac{dv}{dx} is 00.\newlineThe derivative of yy is then xx11.\newlineSimplifying, we get xx22.
  6. Substitute Derivative of Inside Function: Substitute the derivative of the inside function into the derivative of yy.\newlineFrom Step 33, we have ddx[ln(6x56x4)]=(16x56x4)(30x424x3)\frac{d}{dx}[\ln(-6x^5-6x^4)] = \left(\frac{1}{-6x^5-6x^4}\right) * (-30x^4 - 24x^3).\newlineSo, y=(1ln(6))(16x56x4)(30x424x3)y' = \left(\frac{1}{\ln(6)}\right) * \left(\frac{1}{-6x^5-6x^4}\right) * (-30x^4 - 24x^3).
  7. Simplify Derivative Expression: Simplify the expression for the derivative. y=1ln(6)30x424x36x56x4y' = \frac{1}{\ln(6)} \cdot \frac{-30x^4 - 24x^3}{-6x^5-6x^4}.
  8. Factor Out Common Terms: Factor out common terms and simplify further if possible.\newlineWe can factor out 6x3-6x^3 from the numerator and denominator.\newliney=(1ln(6))6x3(5x+4)6x3(x+1)y' = (\frac{1}{\ln(6)}) \cdot \frac{-6x^3(5x + 4)}{-6x^3(x + 1)}.\newlineAfter canceling out 6x3-6x^3 from the numerator and denominator, we get:\newliney=(1ln(6))5x+4x+1y' = (\frac{1}{\ln(6)}) \cdot \frac{5x + 4}{x + 1}.

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