Q. Find the derivative of the following function.y=log6(−6x5−6x4)Answer: y′=
Identify Function and Derivative: Identify the function and the type of derivative to be found.We are given the function y=log6(−6x5−6x4) and we need to find its derivative with respect to x.
Apply Chain Rule for Logarithmic Differentiation: Apply the chain rule for logarithmic differentiation.The chain rule states that the derivative of logb(u(x)) is (1/u(x))⋅(du/dx), where b is the base of the logarithm and u(x) is the function inside the logarithm.
Differentiate Inside Function: Differentiate the inside function −6x5−6x4 with respect to x. The derivative of −6x5 is −30x4 and the derivative of −6x4 is −24x3. So, the derivative of the inside function is −30x4−24x3.
Apply Change of Base Formula: Apply the change of base formula for logarithms. The change of base formula is logb(a)=logc(b)logc(a), where c is a new base. We can use the natural logarithm (base e) for this purpose. So, y=log6(−6x5−6x4) can be rewritten as y=ln(6)ln(−6x5−6x4).
Differentiate Using Quotient Rule: Differentiate y with respect to x using the quotient rule.The quotient rule is (v⋅(dxdu)−u⋅(dxdv))/v2, where u is the numerator and v is the denominator.Here, u=ln(−6x5−6x4) and v=ln(6). Since ln(6) is a constant, its derivative dxdv is 0.The derivative of y is then x1.Simplifying, we get x2.
Substitute Derivative of Inside Function: Substitute the derivative of the inside function into the derivative of y.From Step 3, we have dxd[ln(−6x5−6x4)]=(−6x5−6x41)∗(−30x4−24x3).So, y′=(ln(6)1)∗(−6x5−6x41)∗(−30x4−24x3).
Simplify Derivative Expression: Simplify the expression for the derivative. y′=ln(6)1⋅−6x5−6x4−30x4−24x3.
Factor Out Common Terms: Factor out common terms and simplify further if possible.We can factor out −6x3 from the numerator and denominator.y′=(ln(6)1)⋅−6x3(x+1)−6x3(5x+4).After canceling out −6x3 from the numerator and denominator, we get:y′=(ln(6)1)⋅x+15x+4.
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