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Find the derivative of the following function.

y=log_(5)(4x^(5)-9x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=log5(4x59x4) y=\log _{5}\left(4 x^{5}-9 x^{4}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=log5(4x59x4) y=\log _{5}\left(4 x^{5}-9 x^{4}\right) \newlineAnswer: y= y^{\prime}=
  1. Identify function & derivative type: Identify the function and the type of derivative to be found. We need to find the derivative of the function yy with respect to xx, where y=log5(4x59x4)y=\log_5(4x^5-9x^4). This is a logarithmic differentiation problem.
  2. Apply chain rule for differentiation: Apply the chain rule for logarithmic differentiation.\newlineThe chain rule states that the derivative of logb(u(x))\log_b(u(x)) is (1/u(x))(du/dx)(1/u(x)) \cdot (du/dx), where bb is the base of the logarithm and u(x)u(x) is the function inside the logarithm. We also need to apply the change of base formula for logarithms because the base is 55, not ee (the natural logarithm base).
  3. Change base of logarithm: Change the base of the logarithm from 55 to ee. Using the change of base formula, log5(u)=ln(u)ln(5)\log_5(u) = \frac{\ln(u)}{\ln(5)}, where ln\ln is the natural logarithm. So, y=ln(4x59x4)ln(5)y = \frac{\ln(4x^5-9x^4)}{\ln(5)}.
  4. Differentiate using quotient rule: Differentiate the function using the quotient rule.\newlineThe quotient rule states that the derivative of a function v(x)/w(x)v(x)/w(x) is (v(x)w(x)v(x)w(x))/(w(x))2(v'(x)w(x) - v(x)w'(x))/(w(x))^2. However, since ln(5)\ln(5) is a constant, the derivative of yy with respect to xx is simply the derivative of ln(4x59x4)\ln(4x^5-9x^4) divided by ln(5)\ln(5).
  5. Differentiate inside function: Differentiate the inside function 4x59x44x^5-9x^4 with respect to xx. The derivative of 4x54x^5 is 20x420x^4, and the derivative of 9x4-9x^4 is 36x3-36x^3. So, the derivative of 4x59x44x^5-9x^4 with respect to xx is 20x436x320x^4 - 36x^3.
  6. Apply chain rule for derivative: Apply the chain rule to find the derivative of yy. The derivative of yy with respect to xx is 14x59x4\frac{1}{4x^5-9x^4} * 20x436x320x^4 - 36x^3.
  7. Combine results from Steps 33 and 66: Combine the results from Steps 33 and 66.\newlineThe derivative of yy with respect to xx is (14x59x4)(20x436x3ln(5))\left(\frac{1}{4x^5-9x^4}\right) \cdot \left(\frac{20x^4 - 36x^3}{\ln(5)}\right).
  8. Simplify the expression: Simplify the expression.\newlineThe derivative of yy with respect to xx is 20x436x3ln(5)(4x59x4)\frac{20x^4 - 36x^3}{\ln(5) \cdot (4x^5-9x^4)}.

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