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Find the derivative of the following function.

y=log_(2)(-5x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=log2(5x4) y=\log _{2}\left(-5 x^{4}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=log2(5x4) y=\log _{2}\left(-5 x^{4}\right) \newlineAnswer: y= y^{\prime}=
  1. Identify Function and Base: Identify the function and the base of the logarithm.\newlineWe have the function y=log2(5x4)y = \log_2(-5x^4), where the base of the logarithm is 22. We need to find the derivative of this function with respect to xx.
  2. Apply Chain Rule: Apply the chain rule for differentiation. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is log2(u)\log_2(u) and the inner function is u=5x4u = -5x^4.
  3. Differentiate Outer Function: Differentiate the outer function.\newlineThe derivative of log2(u)\log_2(u) with respect to uu is 1uln(2)\frac{1}{u \cdot \ln(2)} because the change of base formula tells us that log2(u)=ln(u)ln(2)\log_2(u) = \frac{\ln(u)}{\ln(2)}. Therefore, the derivative of the outer function is 1(5x4ln(2))\frac{1}{(-5x^4 \cdot \ln(2))}.
  4. Differentiate Inner Function: Differentiate the inner function.\newlineThe inner function is u=5x4u = -5x^4. The derivative of 5x4-5x^4 with respect to xx is 20x3-20x^3.
  5. Apply Chain Rule Multiplication: Apply the chain rule by multiplying the derivatives of the outer and inner functions.\newlineThe derivative of yy with respect to xx is 1(5x4ln(2))(20x3)\frac{1}{(-5x^4 \cdot \ln(2))} \cdot (-20x^3).
  6. Simplify Expression: Simplify the expression.\newlineWe can simplify the expression by multiplying the constants and canceling out one xx from the numerator and denominator. This gives us y=20x35x4ln(2)=4xln(2)y' = \frac{-20x^3}{-5x^4 \cdot \ln(2)} = \frac{4}{x \cdot \ln(2)}.
  7. Check Final Answer: Check for any possible math errors and write the final answer.\newlineWe have followed the chain rule correctly and simplified the expression without making any algebraic errors. The final answer is y=4xln(2)y' = \frac{4}{x \cdot \ln(2)}.

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