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Find the derivative of 
-7x^(2)y^(4)-4xy^(3)=x+3 using implicit differentiation.

Find the derivative of 7x2y44xy3=x+3 -7 x^{2} y^{4}-4 x y^{3}=x+3 using implicit differentiation.

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Q. Find the derivative of 7x2y44xy3=x+3 -7 x^{2} y^{4}-4 x y^{3}=x+3 using implicit differentiation.
  1. Differentiate with respect to xx: Differentiate both sides of the equation with respect to xx. We will use the product rule for differentiation, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. We will also use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Differentiate the left side: ddx(7x2y4)=7ddx(x2y4)\frac{d}{dx}(-7x^{2}y^{4}) = -7 \cdot \frac{d}{dx}(x^{2}y^{4}) ddx(4xy3)=4ddx(xy3)\frac{d}{dx}(-4xy^{3}) = -4 \cdot \frac{d}{dx}(xy^{3}) Differentiate the right side: ddx(x+3)=ddx(x)+ddx(3)\frac{d}{dx}(x+3) = \frac{d}{dx}(x) + \frac{d}{dx}(3)
  2. Apply product rule: Apply the product rule to the terms involving both xx and yy. For 7x2y4-7x^{2}y^{4}, we have two functions: x2x^{2} and y4y^{4}. Their derivatives are 2x2x and 4y3dydx4y^{3}\frac{dy}{dx}, respectively, since yy is a function of xx and we are differentiating with respect to xx. For yy00, we have two functions: xx and yy22. Their derivatives are yy33 and yy44, respectively. Now apply the product rule: yy55 yy66
  3. Differentiate right side: Differentiate the right side of the equation.\newlineThe derivative of xx with respect to xx is 11, and the derivative of a constant, 33, is 00.\newlineSo, ddx(x+3)=1+0=1\frac{d}{dx}(x+3) = 1 + 0 = 1.
  4. Write down derivatives: Write down the derivatives we found in Steps 22 and 33.\newline7(2xy4+x24y3dydx)4(y3+x3y2dydx)=1-7 \cdot (2x \cdot y^{4} + x^{2} \cdot 4y^{3}\frac{dy}{dx}) - 4 \cdot (y^{3} + x \cdot 3y^{2}\frac{dy}{dx}) = 1
  5. Simplify equation: Simplify the equation by distributing the constants and combining like terms. \newline14xy428x2y3dydx4y312xy2dydx=1-14x \cdot y^{4} - 28x^{2} \cdot y^{3}\frac{dy}{dx} - 4y^{3} - 12xy^{2}\frac{dy}{dx} = 1
  6. Isolate terms: Isolate terms involving dydx\frac{dy}{dx} on one side of the equation and the rest on the other side.\newline28x2y3dydx12xy2dydx=1+14xy4+4y3-28x^{2} \cdot y^{3}\frac{dy}{dx} - 12xy^{2}\frac{dy}{dx} = 1 + 14x \cdot y^{4} + 4y^{3}
  7. Factor out dydx\frac{dy}{dx}: Factor out dydx\frac{dy}{dx} from the left side of the equation.\newlinedydx(28x2y312xy2)=1+14xy4+4y3\frac{dy}{dx}(-28x^{2} \cdot y^{3} - 12xy^{2}) = 1 + 14x \cdot y^{4} + 4y^{3}
  8. Solve for dydx\frac{dy}{dx}: Solve for dydx\frac{dy}{dx}.dydx=(1+14xy4+4y3)(28x2y312xy2)\frac{dy}{dx} = \frac{(1 + 14x \cdot y^{4} + 4y^{3})}{(-28x^{2} \cdot y^{3} - 12xy^{2})}

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