Q. Find the derivative of −7x2y4−4xy3=x+3 using implicit differentiation.
Differentiate with respect to x: Differentiate both sides of the equation with respect to x. We will use the product rule for differentiation, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. We will also use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Differentiate the left side: dxd(−7x2y4)=−7⋅dxd(x2y4)dxd(−4xy3)=−4⋅dxd(xy3) Differentiate the right side: dxd(x+3)=dxd(x)+dxd(3)
Apply product rule: Apply the product rule to the terms involving both x and y. For −7x2y4, we have two functions: x2 and y4. Their derivatives are 2x and 4y3dxdy, respectively, since y is a function of x and we are differentiating with respect to x. For y0, we have two functions: x and y2. Their derivatives are y3 and y4, respectively. Now apply the product rule: y5y6
Differentiate right side: Differentiate the right side of the equation.The derivative of x with respect to x is 1, and the derivative of a constant, 3, is 0.So, dxd(x+3)=1+0=1.
Write down derivatives: Write down the derivatives we found in Steps 2 and 3.−7⋅(2x⋅y4+x2⋅4y3dxdy)−4⋅(y3+x⋅3y2dxdy)=1
Simplify equation: Simplify the equation by distributing the constants and combining like terms. −14x⋅y4−28x2⋅y3dxdy−4y3−12xy2dxdy=1
Isolate terms: Isolate terms involving dxdy on one side of the equation and the rest on the other side.−28x2⋅y3dxdy−12xy2dxdy=1+14x⋅y4+4y3
Factor out dxdy: Factor out dxdy from the left side of the equation.dxdy(−28x2⋅y3−12xy2)=1+14x⋅y4+4y3
Solve for dxdy: Solve for dxdy.dxdy=(−28x2⋅y3−12xy2)(1+14x⋅y4+4y3)