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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an 
(x,y) point.

y=-x^(2)-7
Answer:

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x27 y=-x^{2}-7 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x27 y=-x^{2}-7 \newlineAnswer:
  1. Identify Vertex Form: The vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. To find the vertex of the parabola y=x27y = -x^2 - 7, we need to identify the values of hh and kk. Since the equation is already in the form y=a(xh)2+ky = a(x - h)^2 + k, with a=1a = -1, h=0h = 0, and k=7k = -7, we can directly read off the vertex as (h,k)(h, k).
  2. Determine Values: The vertex of the parabola y=x27y = -x^2 - 7 is (0,7)(0, -7) because there is no horizontal shift (h=0h = 0) and the vertical shift (kk) is 7-7.

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