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Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an 
(x,y) point.

y=x^(2)-6
Answer:

Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=x26 y=x^{2}-6 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=x26 y=x^{2}-6 \newlineAnswer:
  1. Identify Vertex: The vertex form of a parabola is given by y=a(xh)2+ky = a(x-h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. To find the vertex of the parabola y=x26y = x^2 - 6, we need to identify the values of hh and kk in this equation.
  2. Determine Coefficients: In the given equation y=x26y = x^2 - 6, the coefficient aa is 11 (since there is no coefficient written, it is understood to be 11), and there is no (xh)(x-h) term, which means h=0h = 0. The constant term is 6-6, which means k=6k = -6. Therefore, the vertex of the parabola is at the point (h,k)=(0,6)(h, k) = (0, -6).
  3. Conclude Vertex: Since we have identified the vertex without needing to complete the square or use any graphing technology, we can conclude that the vertex of the parabola y=x26y = x^2 - 6 is at the point (0,6)(0, -6).

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