Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) point. y=x^(2)-12 x+28 Answer:

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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an  (x,y) point.  y=x^(2)-12 x+28 Answer:

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Identify Vertex Formula: To find the vertex of a parabola given by the equation y = ax^2 + bx + c, we can use the vertex formula for the x-coordinate, which is -b/(2a). In our equation, a = 1 and b = -12.Calculate x-coordinate: Calculate the x-coordinate of the vertex using the formula -b/(2a). Here, b = -12 and a = 1, so the x-coordinate is -(-12)/(2*1) = 12/2 = 6.Find y-coordinate: To find the y-coordinate of the vertex, we substitute the x-coordinate back into the original equation. So we will calculate y when x = 6.Substitute x into equation: Substitute x = 6 into the equation y = x^2 - 12x + 28 to find the y-coordinate. y = (6)^2 - 12(6) + 28 = 36 - 72 + 28.Simplify expression: Calculate the y-coordinate by simplifying the expression: 36 - 72 + 28 = -36 + 28 = -8.Combine coordinates: Combine the x and y coordinates to form the vertex point. The vertex is at the point (6, -8).

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an $(x, y)$ point. $\newline$ $y=x^{2}-12 x+28$ $\newline$ Answer:

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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) (x,y) point.\newliney=x2−12x+28 y=x^{2}-12 x+28 y=x2−12x+28\newlineAnswer:

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an $(x, y)$ point. $\newline$ $y=x^{2}-12 x+28$ $\newline$ Answer: