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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an 
(x,y) point.

y=x^(2)+8
Answer:

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x2+8 y=x^{2}+8 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x2+8 y=x^{2}+8 \newlineAnswer:
  1. Identify Equation Parameters: To find the vertex of a parabola in the form y=ax2+bx+cy = ax^2 + bx + c, we can use the vertex formula x=b2ax = -\frac{b}{2a}. In this case, the equation is y=x2+8y = x^2 + 8, which means a=1a = 1 and b=0b = 0.
  2. Calculate x-coordinate: Since b=0b = 0, the formula simplifies to x=0/(21)=0x = -0/(2\cdot1) = 0. This gives us the xx-coordinate of the vertex.
  3. Substitute xx into Equation: To find the yy-coordinate of the vertex, we substitute the xx-coordinate back into the original equation. So we substitute x=0x = 0 into y=x2+8y = x^2 + 8.
  4. Calculate y-coordinate: Substituting x=0x = 0 gives us y=(0)2+8=0+8=8y = (0)^2 + 8 = 0 + 8 = 8. This is the y-coordinate of the vertex.
  5. Find Vertex: Combining the xx and yy coordinates, we get the vertex of the parabola as (0,8)(0, 8).

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