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Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an 
(x,y) point.

y=2x^(2)-8
Answer:

Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=2x28 y=2 x^{2}-8 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=2x28 y=2 x^{2}-8 \newlineAnswer:
  1. Identify Vertex Form: The vertex form of a parabola is given by y=a(xh)2+ky = a(x-h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. To find the vertex of the given parabola y=2x28y = 2x^2 - 8, we need to complete the square or use the vertex formula h=b2ah = -\frac{b}{2a} for a parabola in standard form y=ax2+bx+cy = ax^2 + bx + c. Since there is no bxbx term in the given equation, b=0b = 0. Therefore, we can directly apply the vertex formula.
  2. Apply Vertex Formula: Using the vertex formula h=b2ah = -\frac{b}{2a}, we substitute a=2a = 2 and b=0b = 0 into the formula to find the x-coordinate of the vertex.\newlineh=022=0h = -\frac{0}{2\cdot 2} = 0\newlineThe x-coordinate of the vertex is 00.
  3. Calculate Coordinates: To find the y-coordinate of the vertex, we substitute the x-coordinate back into the original equation y=2x28y = 2x^2 - 8.\newliney=2(0)28=8y = 2(0)^2 - 8 = -8\newlineThe y-coordinate of the vertex is 8-8.
  4. Final Vertex: The coordinates of the vertex of the parabola are (0,8)(0, -8).

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