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Find the 
65^("th ") term of the arithmetic sequence 
-26,-11,4,dots
Answer:

Find the 65th  65^{\text {th }} term of the arithmetic sequence 26,11,4, -26,-11,4, \ldots \newlineAnswer:

Full solution

Q. Find the 65th  65^{\text {th }} term of the arithmetic sequence 26,11,4, -26,-11,4, \ldots \newlineAnswer:
  1. Use Formula: To find the 65th65^{th} term of an arithmetic sequence, we need to use the formula for the nthn^{th} term of an arithmetic sequence, which is:\newlinean=a1+(n1)da_n = a_1 + (n - 1)d\newlinewhere ana_n is the nthn^{th} term, a1a_1 is the first term, nn is the term number, and dd is the common difference between the terms.
  2. Identify First Term: First, we identify the first term a1a_1 of the sequence, which is given as 26-26.
  3. Find Common Difference: Next, we need to find the common difference dd. We can do this by subtracting the first term from the second term: d=11(26)=11+26=15d = -11 - (-26) = -11 + 26 = 15
  4. Calculate 6565th Term: Now that we have the first term and the common difference, we can find the 6565th term (a65a_{65}) using the formula:\newline$a_{\(65\)} = a_1 + (\(65\) - \(1\))d
  5. Substitute Values: Substitute the known values into the formula: \(a_{65} = -26 + (65 - 1) \times 15\)
  6. Perform Calculation: Perform the calculation:\(\newline\)\(a_{65} = -26 + (64 \times 15)\)\(\newline\)\(a_{65} = -26 + 960\)\(\newline\)\(a_{65} = 934\)

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